Re: [SQL] How To Use JOIN? - Mailing list pgsql-sql

At 18:05 +0200 on 17/11/98, Takashi Tokunaga wrote:


> 3. Now after that worked without any problem, so I now create SELECT
>    statement:
>
>   select * from test1 test2 where code_1 = test.code_2 \g
>   ERROR:  attribute 'code_2' not found
>
> nope that didn't work
>
>   select test1.name_1 from test1 test2 where test1.code_1 = test2.code_2 \g
>   ERROR:  attribute 'code_2' not found

You seem to have forgotten a comma...

SELECT *
FROM test1, test2   <---- Here
WHERE code1 = code2;

if you don't put a comma, "test2" will be used as an alias to "test1", not
as a table on its own.

Herouth

--
Herouth Maoz, Internet developer.
Open University of Israel - Telem project
http://telem.openu.ac.il/~herutma